A0.650 kg hammer is moving horizontally at 4.00 m/s when it strikes a nail and comes to rest after driving it 1.00 cm into a board. (a) calculate the duration of the impact.
(b) what was the average force exerted on the nail?

a) 0.005s

b) F = -520 N , this is taking the direction into account.

Explanation:

let d be the distance covered by the hummer and nail, a be the acceleration of the hummer and nail

a)   m = 0.650 kg

     Vi = 4.00 m/s

      d = 0.01 m

(Vf)^2 = (Vi)^2 + 2(a)(d)

      0 = (4)^2 + 2(a)(0.01)

      a = -800 m/s^2

then:

Vf = Vi + at

0 = 4 + (-800)t

 t = 0.005s

Therefore, the impact lasted for 0.005s.

b)  the average force is given by:

F = ma = (0.650)(-800) =  - 520 N

Therefore, the magnitude of the average force is 520 N.

c, 1a hope this

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz