When starting a foot race, a 70.0kg sprinter exerts an average force of 650 n backward on the ground for 0.800 s. how far does he travel? a)1.48 m (b) 2.97m (c) 5.95 m (d) 11.9m

Answer is option b) 2.97m

Explanation:

With the relationship between the force exerted by the runner and the mass that it has, I can determine the acceleration it will have:

F= m × a ⇒ a= (650 kg ×(m/s^2)) / (70kg)= 9.286 (m/s^2)

With the acceleration that prints the force exerted and the time I can determine the distance traveled in the interval:

Distance= (1/2) × a × t^2 = (1/2) × 9.286 (m/s^2) × ((0.8s)^2)= 2.97m

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