Suppose you start an antique car by exerting a force of 300 n on its crank for 0.250 s. what angular momentum (in kgm2s ) is given to the engine if the handle of the crank is 0.300 m from the pivot and the force is exerted to create maximum torque the entire time?

The angular momentum is 22.5 kgm²/s.

Explanation:

Given that,

Force = 300 N

Time = 0.250 s

Distance = 0.300 m

We need to calculate the torque

The torque is the product of the force and distance.

Using formula of torque

Where, F = force

r = distance

Put the value into the formula

We need to calculate the angular momentum

The torque is equal to the rate of change of angular momentum of the particle.

We know,

Initial angular momentum is zero.

So,

Put the value into the formula

Hence, The angular momentum is 22.5 kgm²/s.

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