An indestructible bullet 2.27 cm long is fired
straight through a board that is 8 cm thick.
the bullet strikes the board with a speed of
401 m/s and emerges with a speed of 265 m/s.
what is the average acceleration of the bullet through the board?
answer in units of m/s
2

Explanation:

We can assume that the bullet decelerates only when it is passing through the board, from the moment it starts touching the board until it leaves it completely; so, it accelerates for a total distance of

d = 2.27 cm + 8 cm = 10.27 cm = 0.103 m

So we can use the following equation to find its acceleration:

where

v = 265 m/s is the final speed of the bullet

u = 401 m/s is its initial speed

a is the acceleration

d = 0.103 m

Solving for a,

. west

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr