A0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 n/m. the simple harmonic motion that occurs has a maximum speed of 1.9 m/s. determine the amplitude a of the motion. a = entry field with correct answer .07756

The amplitude of the motion is 0.077 m

Explanation:

It is given that,

Mass of the object, m = 0.2 kg

Spring constant, K = 120 N/m

Maximum speed of the object, v = 1.9 m/s

We know that, in harmonic motion, the maximum speed of the object is given by :

Where

A is the amplitude of the wave

is the angular velocity,

A = 0.077 m

So, the amplitude of the motion is 0.077 m. Hence, this is the required solution.                                          

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