Piston in a gasoline engine is in simple harmonic motion. the engine is running at the rate of 2 940 rev/min. taking the extremes of its position relative to its center point as ±5.50 cm.(a) find the magnitude of the maximum velocity of the piston. 16.93 correct: your answer is correct. m/s(b) find the magnitude of the maximum acceleration of the piston

The the magnitude of the maximum velocity and acceleration are 16.93 m/s and .

Explanation:

Given that,

Rate = 2940 rev/min

Amplitude = ±5.50 cm

(a). We need to calculate the magnitude of the maximum velocity

Using formula of maximum velocity

Where, A = amplitude

Put the value into the formula

(b). We need to calculate the maximum acceleration

Using formula of maximum acceleration

Hence, The the magnitude of the maximum velocity and acceleration are 16.93 m/s and .