A30 cm wrench is used to loosen a bolt with a force applied 0.3 mm from the bolt. it takes 60 n to loosen the bolt when the force is applied perpendicular to the wrench. how much force would it take if the force was applied at a 30 degree angle from perpendicular?

The magnitude of force required when the force is applied to an angle is 69.28 N.

The given parameters;

The torque applied in loosening the bolt is calculated as follows;

τ = Fr

τ = 60 x 0.3

τ = 18 Nm

The magnitude of force required when the force is applied to an angle is calculated as follows;

Thus, the magnitude of force required when the force is applied to an angle is 69.28 N.

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The torque required to loosen the bolt when perpendicular was:

t = 60N x 0.3 = 18 Nm

To have the same torque applied at 30 degrees:

18 Nm = Force x 0.3cos(30 degrees)

Simplify:

18 Nm = Force x 0.2598

Force = 18Nm / 0.2598

Force = 69.28 N

Round the answer as needed.