An electron and a proton have the same kinetic energy and are moving at speeds much less than the speed of light. determine the ratio of the de broglie wavelength of the electron to that of the proton.

The ratio of the Broglie wavelength of an electron to that of the proton is 42.85.

Explanation:

let λe be the Broglie wavelength of the electron and λp be the Broglie wavelength of the proton, Me be the mass of the electron and Mp be the mass of the proton. let h be the Planck constant, Kep be the kinetic energy of the proton and KEe be the kinetic energy of the electron

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft