In a double-slit experiment, the third-order maximum for light of wavelength 490 nm is located 12 mm from the central bright spot on a screen 1.6 m from the slits. light of wavelength 630 nm is then projected through the same slits. how far from the central bright spot will the second-order maximum of this light be located?
express your answer to two significant figures and include the appropriate units.

that would be because of both gravity and friction. so     c

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over