An object uniformily accelerates from 15.0m/s west to 35.0 m/s west. what is the magnitude of acceleration if the displacement during this time was 43.0m?

Acceleration, (west)

Explanation:

Initial velocity, u = 15 m/s

Final velocity, v = 35 m/s

Displacement, d = 43 m

We need to find the magnitude of acceleration. Here, both initial and final velocities are in same direction i.e. west, so we have to take both velocities positive. It can be calculated using third equation of motion as :

So, the acceleration of the object is (west) . Hence, this is the required solution.

an energy transformation flow diagram is shown

where is it ?

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.