When landing after a spectacular somersault, a 40.5 kg gymnast decelerates by pushing straight down on the mat. calculate the force she must exert if her deceleration is 7.00 times the acceleration due to gravity in newtons.

F= = 3.18 * 10^3 N

Explanation:

information given:

m= 40.5 kg

a= seven times gravity so we have

a= 7 g

where

gravity = g  =9.8 m/s2

F= m*a

F= (40.5) * 7g

a = 7 g = (7) (9.8) = 68.6 m/s2

There are two forces acts on gymnsat

Where ,w is the weight of Gymnsat

F(net) = F - mg

F- mg = ma

F = mg+ma

so  

F=  m ( g + a)

F = (40.5) [9.8+ 68.6 ]

F = 3.18 * 10^3 N

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.