Atruck using a rope to tow a 2230-kg car accelerates from rest to 13.0 m/s in a time of 15.0s. how strong must the rope be? μk = 0.373

The rope must have a force of 10084,21 N

Explanation

Acceleration calculation

The car acceleration is equal to the acceleration of the truck

ac: car acceleration

at: truck acceleration)

 equation(1)

Known information:

vi = Initial speed = 0, ti = initial time = 0

vf = Final speed = 13 , t = final time =5 s

We replaced the known information in the equation(1):

Dynamic analysis

The forces acting on the car are the following:

Wc: Car weight

N: normal force, road force on the car

Ff: Friction force

T: Force of tension

Car weight calculation:

mc = Car mass = 2230kg

g = Gravity acceleration=9.8

Normal force calculation:

Newton's first law

Friction force calculation (Ff):

We have the formula to calculate the friction force:

Ff = μk * N  Equation (3)

μk kinetic coefficient of friction

We know that μk = 0.373and N= 21854N ,then:

Calculation of the tension force in the rope (T):

Newton's Second law

T=10084,21 N

The rope must have a force of 10084,21 N

sonar - device which is used to find the submit submarines, sankalp ship. sonar waves consists of a transmitter and detector which are installed in the observation centre on board of a ship. the ultrasonic waves are sent into the sea at high frequency about 1000 khz in all direction.