Aroller coaster is traveling at 13m/s when it approaches a hill that is 400 m. long. heading down the hill, it accelerates 4.0m/s^2 . what is the final velocity of the roller coaster?

58.0 m/s

Explanation:

We can solve the problem by using the following SUVAT equation:

where

v is the final velocity of the roller coaster

u = 13 m/s is the initial velocity

a = 4.0 m/s^2 is the acceleration

s = 400 m is the displacement

Substituting and solving for v, we find

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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