Light of wavelength 310 nm strikes a metal whose work function is 2.3 ev. (a) what is the maximum kinetic energy of the ejected electrons? (b) what is the de broglie wavelength for the electrons that are produced?

a.1.71 eV

b.0.939 nm

Explanation:

We are given that

Wavelength of light =310 nm= m

Work function=2.3 eV

Mass of electron=Kg

a.We have to find the maximum kinetic energy of ejected electron

K.E=1.71 eV

Hence, the maximum kinetic energy of ejected electron=1.71  eV

b.Kinetic energy =

p=

p=m-s

We know that de brogile wavelength

Hence, the de-brogile  wavelength of ejected electron=0.939 nm.

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at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.