An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.
find the focal length of the lens, if the image is 26 cm from the lens. the image is real.
a virtual object lies 95 cm in front of a diverging lens, with a 29 cm focal length.
find the location of the image.
find the magnification
is the image real or virtual?

Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

We need to calculate the object distance

We need to calculate the focal length

Using formula of lens

put the value into the formula

The focal length of the lens is 35.52.

(B). Given that,

Object distance = 95 cm

Focal length = 29 cm

We need to calculate the distance of the image

Using formula of lens

Put the value in to the formula

We need to calculate the magnification

Using formula of magnification

The magnification is 0.233.

The image is virtual.

Hence, This is the required solution.

answer: he got 23

explanation:

i think the answer would be b