1. you place an object 63 cm in front of a converging lens, with a 40 cm focal length.
find the location of the image.
find the magnification.
is the image real or virtual?
2. an object is placed to the left of a converging lens of focal length f = 30 cm, such that the object-to-image distance is 5 cm. find the magnification.

1.

109.6 cm ,  - 1.74 , real

2.

1.5

Explanation:

1.

d₀ = object distance = 63 cm

f = focal length of the lens = 40 cm

d = image distance = ?

using the lens equation

d = 109.6 cm

magnification is given as

m = - 1.74

The image is real

2

d₀ = object distance = a

d = image distance = - (a + 5)

f = focal length of lens = 30 cm

using the lens equation

a = 10

magnification is given as

m = 1.5

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j