Assume the assume the same nerve in problem #2 has a diameter of 7.0 um. what is the resistivity and conductivity of the nerve (assumine it to have the same properties as axoplasma)? what would be the nerve resistance and the electromotive force acting through the nerve (using information from #2)?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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