Aresearch van de graaff generator has a 2.10 m diameter metal sphere with a charge of 40.0 c on it. (a) what is the potential (in kv) near its surface? 171.42 x kv (b) at what distance from its center (in m) is the potential 105 kv? m (c) an oxygen atom with three missing electrons is released near the van de graaff generator. what is its kinetic energy in kev at the distance found in part (b)? kev

distance is 3.428571 × m

potential is 342.857143 × kV

kinetic energy is  713.571429 × KeV

Explanation:

Given data

diameter  = 2.10 m

charge = 40.0 C

to find out

potential and distance from its center  and kinetic energy

solution

we know diameter  = 2.10 m so radius will be = 2.10 / 2 = 1.05 m and charge = 40 C

so potential = KQ/R

here K is constant with value = 9× Nm²C²

so  potential =   9× (40) / 1.05

potential = 342.857143 × V

so  potential is 342.857143 × kV

and

in 2nd part we find radius

potential = KQ / R

put the value

105 ×  = 9× ( 40 )   / R

R = 3.428571 × m

so distance is 3.428571 × m

and

in 3rd part

we find KE

so change in KE  = change in V

so KE 2 - KE 1  = q (V2 - V1)

KE2 - 0 = 3 ( 342.857143 × - 105 )

so kinetic energy is  713.571429 × KeV

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explanation: