When a 3 cm tall object is placed 10 cm in front of a concave spherical mirror, a 5 cm tall virtual image is observed behind the mirror. if an object is place 40 cm in front of the mirror, how far in front of this mirror will the real image appear? a) 112 cm b) 66.7 cm e) 56.3 cm c) 87.5 cm d) 150 cm

option B is correct

66.7 cm far from front of this mirror will the real image appear

Explanation:

Given data

object height = 3 cm

concave spherical mirror distance = 10 cm

virtual image from mirror distance = 5 cm

object is place  = 40 cm

to find out

how far in front of this mirror will the real image

solution

we apply here magnification equation that is

magnification = height of image / height of object = - distance of image / distance of object

height of image / height of object = - distance of image / distance of object

5 / 3 = - distance of image / 40

distance of image = - 5/3 × 40

distance of image = - 66.666 cm

here negative sign show that it is real image

so option B is correct

66.7 cm far from front of this mirror will the real image appear

asthenosphere and convection

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.