What is the energy range (in ev) of photons of wavelength 410 nm to 750 nm ? express your answers using two significant figures separated by a comma.

Explanation:

It is given that,

Wavelength 1,

Wavelength 2,

Energy of a photon having wavelength 1 is given by :

Energy of a photon having wavelength 2 is given by :

Hence, this is the required solution.

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0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2