You take a lab battery and, when it isn't connected to a circuit, you measure a voltage of 4.00-v with a voltmeter. you then connect the battery to a 200-12 resistor and measure a current of 17.5-ma. what is the internal resistor of this battery?

Explanation:

As we know that when battery is in open circuit then the potential difference of the cell is known as EMF

so EMF is given as

now when the battery is connected across a resistance of 200 ohm then there is current flowing through the battery

it is given as

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an electric circuit