Aparticle of mass m=0.1 kg is initially at rest at origin. it starts moving with a uniform acceleration a = 10 ms at t=o. the action s of the partice in units of j-s at t=2s is .

40 J-s

Explanation:

Given:

mass of the particle, m=0.1 kg

Acceleration of the particle, a = 10 m/s²

Time interval, ΔT = 2 - 0 = 2 seconds

Since the particle is initially at rest,

therefore the initial speed u = 0 m/s

The action, s is calculated as :

s = Force × distance × time interval

now,

from the Newton's equation of motion, we have

where, S is the distance traveled after 2 seconds

on substituting the values, we have

or

S = 20 m

also,

Force =  mass × acceleration

thus,

Force = 0.1 × 10 = 1 N

on substituting the values, in the formula for the action, we get

s = 1 × 20 × 2

or

s = 40 J-s