Two drops of mercury each has a charge on 0.18 nc and a voltage of 434.21 v. if the two drops are merged into one drop, what is the voltage on this drop?

Explanation:

charge on the drop is given as

V = 434.21 Volts

now we know that

so we have

now when two such drops is merged and forms a single drop then in that case

so we have

now after merging two drops we have total charge on both drops is

now potential of two drops is given as

not too sure thinking it will always be directed towards the centre of the earth. could be wrong not sure

if they have a finite resultant