The work function of osmium is wo = 5.93 ev. (a) what is the maximum wavelength of incident light for which photoelectrons will be released from osmium? 2.09e-7 ✓m (b) what is the minimum frequency of incident light, called the cutoff frequency, for which photoelectrons will be released from osmium? 5.93 your response differs significantly from the correct answer. rework your solution from the beginning and check each step carefully. hz (c) what is the maximum kinetic energy of photoelectrons emitted by osmium if 7.10-ev photons strike its surface? 5.91e-5 your response differs significantly from the correct answer. rework your solution from the beginning and check each step carefully.

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up

wavelength divides in half and speed stays the same.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.