Object a, which has been charged to +13.5 nc, is at the origin. object b, which has been charged to -22.05 nc, is at x=0 and y=1.84 cm. what is the magnitude of the electric force on object a?

7.9 x 10^-3 N attractive in nature

Explanation:

QA = 13.5 nC = 13.5 x 10^-9 C

QB = - 22.05 nC = - 22.05 x 10^-9 C

d = 1.84 cm = 0.0184 m

Let the electric force on object A is F.

By use of Coulomb's law in electrostatics

F = K x QA x QB / d^2

F = (9 x 10^9 x 13.5 x 10^-9 x 22.05 x 10^-9) / (0.0184 x 0.0184)

F = 7.9 x 10^-3 N attractive in nature

i think the answer is a, hope this : )

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)