Aresistor with r = 300 ω and an inductor are connected in series across an ac source that has voltage amplitude 500 v . the rate at which electrical energy is dissipated in the resistor is 296 w part a
what is the impedance z of the circuit?
express your answer to three significant figures and include the appropriate units.
part b
what is the amplitude of the voltage across the inductor?
express your answer to three significant figures and include the appropriate units
part c
what is the power factor?
express your answer using three significant figures.

Explanation:

 Rate of dissipation of energy at resistor

= I² R = 296

current I² = 296/R = 296 / 300

I = 0.9933 A.

Impedence Z = V / I = 500 / .9933

= 503 ohm.

B ) Let it be V

voltage across resistance = 300 x .9933 = 298 v

Now 500² = 298² + V²

V = 401 v

C)  Power factor = R / Z

=300 / 503

= 0.596

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.