An object is 18.0 cm to the left of a lens with a focal length of +9 cm. a second lens of focal length +13 cm is 29.5 cm to the right of the lens. find the location and size of the object of height 4.0 cm. location with respect to the second lens?

99.67 cm to the left of second lens

Explanation:

For the first lens :

= Distance of the object = 18 cm

= focal length of the lens = 9 cm

= Distance of the image

Using the lens equation

 cm

= distance between the two lenses = 29.5 cm

For the second lens, the image formed by the first lens acts as the object

For the second lens :

= Distance of the object = =    =   cm

= Distance of the image

= focal length of the lens = 13 cm

Using the lens equation

 cm

The image is located 99.67 cm to the left of the second lens

connect the batteries in series and hope

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer