A2.0-cm-tall object is 15 cm in front of a diverging mirror that has a -25 cm focal length part a calculate the image position. input positive value if the image is on the same side from the mirror as an object and negative if the image is on the other side. express your answer using two significant figures. part b calculate the image height. input positive value if the image is upright and a negative value if it is inverted. express your answer using two significant figures.

A) - 9.4 cm

B) 1.3 cm

Explanation:

We shall use mirror formula

\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\\

v = ?, u = + 15 cm , f = - 25 cm.

\frac{1}{v}+\frac{1}{15}=\frac{1}{-25}\\

\frac{1}{v}=-\frac{1}{15}-\frac{1}{25}\\

v=\frac{-10-6}{150}

v=-9.375cm

magnification =\frac{v}{u}\\

=\frac{9.375}{15}\\

Size of image = magnification multiply size of object

=\frac{9.375}{15}\times 2\\

1.25cm

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation: