Two protons are 9.261 fm apart. (1 fm= 1 femtometer = 1 x 10^-15 m.) what is the ratio of the electric force to the gravitational force on one proton due to the other proton?

Explanation:

Parameters given:

Distance between the protons, r =

Electric charge of proton, Q =

Mass of proton, m =

The electric force on one proton due to the other given as:

where k = Coulomb's constant

The gravitational force on one proton due to the other is given as:

where G = gravitational constant

Therefore, the ratio of electric force, , and gravitational force, , is:

an electric circuit