For a long ideal solenoid having a circular cross-section, the magnetic field strength within the solenoid is given by the equation b(t) = 5.0t t, where t is time in seconds. if the induced electric field outside the solenoid is 1.1 v/m at a distance of 2.0 m from the axis of the solenoid, find the radius of the solenoid.

Radius of the solenoid is 0.93 meters.

Explanation:

It is given that,

The magnetic field strength within the solenoid is given by the equation,

, t is time in seconds

The induced electric field outside the solenoid is 1.1 V/m at a distance of 2.0 m from the axis of the solenoid, x = 2 m

The electric field due to changing magnetic field is given by :

x is the distance from the axis of the solenoid

, r is the radius of the solenoid

r = 0.93 meters

So, the radius of the solenoid is 0.93 meters. Hence, this is the required solution.

The radius of the solenoid is 0.94 meters.

Explanation:

It is given that,

The magnetic field strength within the solenoid is given by the equation as :

Where

t is the in seconds

The induced electric field outside the solenoid is,

Distance, d = 2 m from the axis of the solenoid

To find,

The radius of the solenoid.

Solution,

The expression for the induced emf is given by :

= magnetic flux

The electric field due to changing magnetic field is given by :

r = 0.9380 m

or

r = 0.94 meters

So, the radius of the solenoid is 0.94 meters. Hence, this is the required solution.

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