Aman pushes an 250-n crate at constant speed a distance of 30.0 m upward along a rough slope that makes an angle of 60° with the horizontal. the work done by the force of gravity is:

6495.19 Joule

Explanation:

F = Weight of the crate = 250 N

d = Distance the cart is pushed = 30 m

θ = Angle of inclination = 60°

The weight of the crate will be resloved into two components

Fdsinθ and Fdcosθ

Work done by the force of gravity is

W = Fdsinθ

⇒W = 250×30×sin60

⇒W = 6495.19 Joule

∴ The work done by the force of gravity is 6495.19 Joule

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im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.