Consider light that has its third minimum at an angle of 23.3° when it falls on a single slit of width 4.05 μm. find the wavelength of the light in nanometers.

The wavelength of light is 533 nm.

Explanation:

It is given that,

Width of a single slit,

Light has its third minimum at an angle of 23.3° when it falls on a single slit. For destructive interference, the equation for minima is given by:

Here, n = 3

So, the wavelength of the light is 533 nm. Hence, this is the required solution.

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