Apilot in a helicopter sights an ambulance heading toward an accident scene. he measures the angles of depression to the ambulance and the accident to be 21o and 15o, respectively. if the helicopter is 4000 ft from the ambulance, how far does the ambulance have to travel to get to the accident?

the ambulance have to travel 4507.847 feet to get to the accident

Explanation:

Let D represent position of ambulance

Let C represent position of accident scene

The situation is represented in the below attached figure

In the figure we have

AB = 4000 feet

Thus in triangle ABC we have

In triangle ABD we have

Thus the distance between the ambulance and accident scene will be 14925.20-10420.356 = 4507.847 feet

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me