A) a mass spectrometer has a velocity selector that allows ions traveling at only one speed to pass with no deflection through slits at the ends. while moving through the velocity selector, the ions pass through a 60,000-n/c e? field and a 0.0500-t b? field. the quantities v? , e? , and b? are mutually perpendicular. determine the speed of the ions that are not deflected. b) after leaving the velocity selector, the ions continue to move in the 0.0500-t magnetic field. determine the radius of curvature of a singly charged lithium ion, whose mass is 1.16

(A). The speed of the ions is

(B). The radius of curvature of a singly charged lithium ion is

Explanation:

Given that,

Electric field = 60000 N/C

Magnetic field = 0.0500 T

(A). We need to calculate the velocity

For no deflection

(B). We need to calculate the radius

Using magnetic force balance by centripetal force

Put the value into the formula

Hence, (A). The speed of the ions is

(B). The radius of curvature of a singly charged lithium ion is

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.