An oil film with refractive index 1.48 and thickness 290 nm is floating on water and illuminated with white light at normal incidence. what is the wavelength of the dominant color in the reflected light?

572.3 nm

Explanation:

= refractive index of the oil film = 1.48

= thickness of the oil film = 290 nm

= wavelength of the dominant color

m = order

Using the equation

For m = 0

= 1716.8 nm

For m = 1

= 572.3 nm

For m = 2

= 343.4 nm

Hence the dominant color wavelength is 572.3 nm

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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