An aluminum wing on a passenger jet is 36m long when its temperature is 18°c. at what temperature would the wing be 3 cm (0.03 m) shorter?

- 16.72° C

Explanation:

L = 36 m

T1 = 18° C

Let it is 3 cm shorter at T2.

ΔL = 3 cm = 0.03 m

ΔT = T1 - T2

coefficient of linear expansion for Aluminium, ∝ = 24 x 10^-6 / °C

Use the formula for the thermal expansion

ΔT = 34.72

T1 - T2 = 34.72

T2 = T1 - 34.72 = 18 - 34.72 = - 16.72° C

answer: good job it's all correct !

explanation:

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.