A1200-turn coil of wire that is 2.3 cm in diameter is in a magnetic field that drops from 0.13 t to 0 t in 12 ms . the axis of the coil is parallel to the field. what is the emf of the coil? express your answer using two significant figures.

The emf of the coil is 21.60 V.

Explanation:

Given that,

Number of turns = 1200

Diameter = 2.3 cm

Time = 12 ms

We need to calculate the magnetic flux

Using formula of flux

The axis of the coil is parallel to the field.

So,

We need to calculate the emf of the coil

Using formula of emf

Hence, The emf of the coil is 21.60 V.

newton's first law of motion

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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