At what rate must the potential difference between the plates of a parallel-plate capacitor with a 2.0 μf capacitance be changed to produce a displacement current of 1.4 a?

7 x 10^5 V/s

Explanation:

capacitance, C = 2 micro farad = 2 x 10^-6 F

displacement current, id = 1.4 A

Let dV/dt be the rate of change of potential difference between the plates of the capacitor.

The relation between the displacement current and the rate of change of potential difference is given by

dV/dt = 7 x 10^5 V/s

Thus, the rate of change of potential difference between the plates is given by 7 x 10^5 V/s.

magnitude and direction

ill do it for 100, also this isnt 80 its 40