A7.50 kg bowling ball moving 8.39 m/s to the right hits a 1.36 kg bowling pin at rest. afterwards, the pin moves 13.9 m/s right. what is the final velocity of the ball?

5.87 m/s

Explanation:

mass of bowling ball, m1 = 7.5 kg

initial velocity of bawling ball, u1 = 8.39 m/s right

mass of bowling pin, m2 = 1.36 kg

initial velocity of bowling pin, u2 = 0

Final velocity of bowling pin, v2 = 13.9 m/s right

Let v1 be the final velocity of bowling ball.

As there is no external force is acting on the system, So the linear momentum of the system is conserved.

Total momentum before hitting = Total momentum after hitting

m1 x u1 + m2 x u2 = m1 x v1 + m2 x v2

7.5 x 8.39 + 1.36 x 0 = 7.5 x v1 + 1.36 x 13.9

62.925 = 7.5 x v1 + 18.904

44.021 = 7.5 x v1

v1 = 5.87 m /s

Thus, the final velocity of bowling ball is 5.87 m/s.

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