Asmall region of space in the shape of a cube of side 1 mm, contains 10.0 j of energy in the form of an electric field. calculate the magnitude of the electric field (vm-1)

electric field is 4.75  ×  V/m

Explanation:

given data

cube of side = 1 mm

energy = 10 J

to find out

magnitude of the electric field

solution

to find electric field

we will apply here energy formula that is

energy  = 1/2 × ∈ × E² × volume   ...............1

here  we know ∈ = 8.85 ×

so put all value to get E electric field

energy  = 1/2 × ∈ × E² × volume

10  = 1/2 × 8.85 ×  × E² × (1/1000)³

solve it and get E

E² = 2× 10 / 8.85 ×  × (1/1000)³

E = 4.75  ×

so  electric field is 4.75  ×  V/m

from

explanation:

wind is defined by the direction it blows from.   for example, a wind blowing from north to south is called a northerly wind.