Aconvex mirror has a radius of curvature of 0.60 m. where must an object be placed in front of the mirror such that the image is formed 0.25 m behind the mirror?

1.5 cm

Explanation:

radius of curvature, R = + 0.60 m

focal length = half of radius of curvature = 0.60 / 2 = + 0.30 m

distance of image from the mirror, v = + 0.25 m

Let the distance of object from the mirror is u.

Use the mirror formula

u = - 1.5 cm

Thus,t the object is placed on the left side of mirror at a distance 1.5 cm .

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

double the distance = divide strength by 4