A145 ω resistor is connected in series with a 66 mh inductor and a 0.3 μf capac- itor. the applied voltage has he form e 190 v sin(2r/t), where the frequency is f 1115 cycles/s. find the rms current answer in units of a 005 (part 2 of 4) 10.0 points find the ms voltage across r. answer in units of v 006 (part 3 of 4) 10.0 points find the ms voltage across l answer in uts of v 007 (part 4 of 4) 10.0 points find the rms voltage across c answer in units of v

0.922 A ,133.761 volt ,426.09 volt,438.90 volt

Explanation:

We have given resistance R=145 OHM

Inductance

Capacitance

Frequency f =1115 Hz

Emf equation = 190 sin(2πft)

So rms voltage

Inductive reactance

Capacitive reactance

Impedance

RMS current

RMS voltage across resistor = 0.922×145=133.761 volt

RMS voltage across inductor =0.922×462.145=426.09 volt

RMS voltage across capacitor =0.922×438.90 volt

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this means that the temperature of both substances will be equal