Atypical home may require a total of 2.00×10^3 kwh of energy per month. suppose you would like to obtain this energy from sunlight, which has an average daylight intensity of 1500 w/m^2 . - assuming that sunlight is available 8.0 h per day, 25 d per month (accounting for cloudy days), and that you have a way to store energy from your collector when the sun isn't shining, determine the smallest collector size that will provide the needed energy, given a conversion efficiency of 26 % .

The the smallest size of the collector is 25.64 m²

Explanation:

Given that,

Total energy

Intensity

Efficiency = 26%

The intensity of light can be transformed to the required energy = Available intensity of light

We need to calculate the smallest size of the collector

Using formula of energy related to the intensity through area and time

Where, E= energy

I = intensity

= time

Put the value into the formula

Hence, The the smallest size of the collector is 25.64 m²

like poles repel so keep pushing north to north and repels funny to see this

v=ir = 3x15 =45 v