A6.00 kg object is lifted vertically through a distance of 5.25 m by a light string under a tension of 80.0 n. find: (2 marks) a. the work done by the force of tension, b. the work done by gravity, and c. the final speed of the object if it starts from rest.

Explanation:

It is given that,

Mas of the object, m = 6 kg

It is lifted through a distance, h = 5.25 m

Tension in the string, T = 80 N

(a) By considering the free body diagram of the object, the forces can be equated as :

Work done by tension,

(b) Work done by gravity,

(c) Let v is the final speed of the object and u = 0

v = 5.91 m/s

Hence, this is the required solution.

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