Ascreen is placed 60.0 cm from a single slit, which is illuminated with light of wavelength 690 nm. if the distance between the first and third minima in the diffraction pattern is 3.10 mm, what is the width of the slit?

slit width, b = 0.2671 mm

Given:

distance of screen from the slit, x = 60.0 cm

wavelength of light,

distance between 1st and 3rd minima, t = 3.10 mm =

Solution:

Calculation of the distance between 1st and 3rd minima:

b = 0.2671 mm

slit width, b = 0.2671 mm

. west

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day