1) a 1.0 kg mass is located at the origin of the (x, y) plane, another 1.0 kg mass is located at the point (0.12, 0), and a 2.0 kg mass is located at the point (0.06, 0.08), where the (x, y) coordinates are given in meters. the three masses are fixed relative to each other by massless rods. a) find the moment of inertia of this object about an object perpendicular to the (x, y) plane & passing through the 2.0 kg mass.
b) use the parallel axis theorem to find the moment of inertia about an axis passing through the center of mass & perpendicular to the (x, y) plane.
c) find the moment of inertia about an axis that passes through both of the 1.0 kg masses

Work is reduced while time is decreased

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.