If an engine at sea level produces 100 horsepower, how many horsepower would it develop at 6,000 feet of altitude?

Power develop at 6000 ft = 100 - 18 = 82 hp

Given:

Power produced by the engine at sea level = 100 hp

Explanation:

For each 1000 ft rise above the sea level, the power loss of the engine is about 3%

Therefore,

1000 ft - 3% loss

6000 ft -

At 6000 ft, the power loss is 18% or 18 hp

Now,

Power develop at 6000 ft = Power at sea level - Power loss at 6000 ft

Power develop at 6000 ft = 100 - 18 = 82 hp

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

multiply 2kg by latent heat of vap