An inductor and a resistor are connected in series. when connected to a 60-hz, 90-v (rms) source, the voltage drop across the resistor is found to be 51 v (rms) and the power delivered to the circuit is 17 w. (a) find the value of the resistance.
(b) find the value of the inductance.

resistance = 154.54 ohm

inductance is 59.60%

Explanation:

given data

frequency f = 60 Hz

V rms = 90 V

V rms =51 V

power P = 17 W

to find out

resistance and inductance

solution

we will apply here power formula here to find current I

power = I ( Vrms)

I = 17 / 51 = 0.33

current I = 0.33 A

so resistance formula is

resistance = V / I

resistance = 51 / 0.33

resistance = 154.54 ohm

and

we know inductance L formula

x = 2πfL

so L = x / 2πf   a

we know

x = √(Z² - R²)

x = √((90/0.33)² - (154.54²))

x = 224.71

so from equation a

L = 224.71 / 2π(60)

L = 0.5960

so  inductance is 59.60%

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

a is the best answer your welcome