Engineers want to design seats in commercial aircraft so that they are wide enough to fit 95% of all males. (accommodating 100% of males would require very wide seats that would be much too expensive.) men have hip breadths that are normally distributed with a mean of 14.2 in. and a standard deviation of 0.9 in. find upper p 95. that is, find the hip breadth for men that separates the smallest 95% from the largest 5%.

The answer is 15.68 in

Explanation:

X~N(μ=14.2; σ=0.9)

I want to find "a", so:

Z~N(0; 1)

Φ(-15.78)≅0

Based on the Standard Normal table

if

(a-14.2)/0.9=1.64485, then a=15.68

object 2 because all the other ones are wrong

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.