Abee flies at a constant rate of 5 m s until it notices a flower. it then comes to rest in 5 seconds. find the acceleration of the bee if a= ? v ? t . a) -5 m s2 b) -1 m s2 c) 1 m s2 d) 5 m s2

B) -1m/s^2

Explanation:

Final speed = 0 m/s

Initial speed = 5m/s

Time taken for it to come to rest(0m/s) = 5

then use the formula;

[v = u + at],where v is the final speed..u is the initial speed..t is time taken for it to come to rest and a is the acceleration

; 0 = 5 + 5a

; -5 = 5a

;Acceleration = -1 m/s^2

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

2b2t

explanation:

2b2t